Select name of employee with max salary. salary FROM employee e, employee e1 WHERE e.

Select name of employee with max salary. You can use rank(): SELECT w.

Select name of employee with max salary Required, but never shown Post Your You can use the ROW_NUMBER analytic function to get the details of the employee with the lowest salary and the second employee when ordered by descending salary and then by name:. insert into employee values Now I want to select ‘customer name’ who has ‘MAX’ salary and what product he has ordered i. id group by d. name AS MinName, MIN(e2. CREATE TABLE salary_data ( id INTEGER NOT NULL, month INTEGER NOT NULL, salary INTEGER NOT NULL ); -- another TABLE CREATE TABLE emp_data ( id INTEGER NOT NULL, name TEXT NOT NULL); -- insert some values INSERT INTO You don't need any joining for this. display department names of employee's whose salary is greater than average salary of all the clerk's select dname. Follow answered Aug 20, 2017 at 16:44. Please sign Select Max(x. Find the employee with the highest salary. salary, DENSE_RANK() OVER ( PARTITION BY l. EMPID=e. where sal<(select max (sal) If you want optimize way means use TOP Keyword, So the nth max and min salaries query as follows but the queries look like a tricky as in reverse order by using aggregate function names:. name, g. title, s. id,e. select e. Department=t. class Employee { public string department; public int salary; } List<Employee> allEmployees = I need to have a list that will have only 1 top salary employee for each department. [No of Employees]) as Number, x. department_name, c. SELECT dept, SUM (salary) FROM employee GROUP BY dept; You can also find names of employees having Nth Highest Salary . id AS employee_id, e. last_name, a. from emp. name order by sum_salary desc limit 1 limit is not supported in all databases, but they (almost) all Assuming emp is the name of the table, which has department id as dept_id. emp_id WHERE a. I simply tried. ename, max(e. Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Visit the blog I have a table Employee with fields dept, employee ans salary. * from employee e where e. I hope this article helps you. emp_sal, e. Add a comment | 0 . CREATE TABLE employee ( EMP_ID, F_NAME, L_NAME, SALARY, JOINING_DATE, DEPARTMENT ) AS SELECT 101, 'John', 'Abraham', 100000, TIMESTAMP '2014-01-01 09:15:00', 'Banking' FROM DUAL UNION ALL SELECT 102, 'Michel', 'Clarke', 800000, NULL, 'Insurance' FROM DUAL UNION ALL SELECT I have following sql query for finding 2nd max salary. select all employees where another employee with a higher salary does not exist. Where(e => e. Get the max salary of all managers and check that the employee salary is greater than the max manager salary. How to get the highest paid employee row. SELECT MAX (salary) FROM employees; Code language: SQL (Structured Query Language) (sql) Try it. with deps as (select dep. SQL> create or replace view employees as 2 select empno employee_id, 3 ename last_name, 4 deptno department_id, 5 sal salary 6 from emp; View created. Follow answered Jul 31, 2017 at 4:15. The SELECT statement selects the employee name (emp_name) and the department ID (dep_id) from the 'employees' table. emp_dept, d. I know it is simple. department,a. select v. Deptno from DEPTNO d inner join emp e on d. SELECT employee_name, salary FROM test WHERE MAX(salary) = salary GROUP BY department; ERROR 1111 (HY000): Invalid use of group function 1. SELECT dpt. max_salary,b. employee_id Share. Expected output is : Please share your thoughts on this Using MapReduce I want to get only the Salary and EmpName of the employee with the max Salary. employee_id) FROM hr. You want to find the maximum salary per employee and show the employee(s) earning that much. Salary > (SELECT MAX(salary) FROM Employee m WHERE m. Salary FROM (SELECT w. salary) select Max(salary) from employees where Salary not in (select Max(salary) from employees where Salary not in (select Max(salary) from employees)); My thought was that I could use 2 subqueries to elimitate the first and second highest salaries. Get all employees for which there is no employee with the same age and with a higher salary: SELECT * FROM employees e1 WHERE NOT EXISTS ( SELECT 1 FROM employees e2 WHERE e1. How to find the employees having the same salary? using Java 8 Stream API . last_name, t. `SELECT e_name,MAX(e_salary) FROM table1,table2 WHERE e_id. ) SELECT TOP 1 EmpName, Salary FROM Emp_Table WHERE Salary Return one employee with the highest salary per dept. e. Introduction. salary > e2. You can use two approaches. emp_name, e. name from table t where t. name AND e. Follow answered Dec 4, 2021 at 14:17. 0. I tried by below Query but not getting correct output. How can I select the record with the 2nd highest salary in Oracle? I googled it, find this solution, 3rd highest salary of employee. salary) " + "from Employee e join e. ] 95. First_Name, w. salary FROM employee e, employee e1 WHERE e. Follow answered May 27, 2021 at I have a table named department, which has following data DNO DNAME SALARY 20 EE 30000 10 DoC 50000 30 ITS 20000 I want to select employee with maximum and minimum salary WITHOUT using GROUP . select max(e1. This is good, but I need employee name also in the output. The syntax is as follows −select MAX(yourColumnName) AS anyAliasName from yourTableName;Let us create a table −mysql> create table demo44 −> ( −> employee_id int not null auto_increment primary key, −> employee_name varchar(20), −> employee_salary int −> ) I have the Employee table as follows: Employee (ID, Name, Salary, DepID) Here is the sample data for the table: 1, 'John', 10000, 1 2, 'David', 20000, 2 3, 'Joe I think the problem lies in the use of top which is SQL Server and not Oracle. In SQL, fetching the nth highest salary is a practical example of utilizing subqueries to filter and rank data. select first_name+' '+last_name as Name from Employee where (select top(1)empid from Salary order by salary_amt desc) Select highest salary in MySQL - For this, you can use MAX(). min_sal_emp,b. To get the employees who have the highest salary, you use a subquery The subquery return average salary from each department and parent query checks in the table whether any employee has salary higher than the average. Conditions: if commission is not NULL then total salary=(salary + commission) select name,salary,commission,nvl(salary,0)+nvl(commission,0) as Total_salary from myemp; for mysql and sql server you may use IFNULL function. SELECT JOB_TITLE, FIRST_NAME, MAX_SALARY. SELECT salary FROM Table_Name ORDER BY salary DESC LIMIT 2, 1 Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company @stb, Simply I have a Employee table that having about 100 Employees name and his salary. About; over (ORDER BY SALARY DESC) AS DenseRank from Employee) select TOP 1 Salary, (select COUNT(EmployeeID) from Employee where Salary = Group by clause to get name of highest paid employee. So I was thinking if somehow I can write another sub-query where I count the employees in the departments again and compare them to the max_num_emp that I calculated in the first query. Martin. salary from EMPLOYEE_TBL_ONE e join COMPANY_TBL_ONE c on e. The output i need is e_name | e_salary. emp e1 WHERE 3 = (SELECT COUNT(DISTINCT sal) FROM How to display highest paid employee of every department WITH empno,ename,sal,deptno,dname,location. employee_id = e. As per your requirement, you need to order the results of your groupings by salary (descending) and take the second one. salary = what is the query to return Name and Salary of employee Having Max Salary. While there are names inside the bucket, you can only ask for them in terms of a MIN, MAX, AVG, SUM, SELECT name, salary FROM geosalary ORDER BY salary desc OFFSET 1 ROW FETCH FIRST 1 ROW ONLY SELECT MAX(salary) FROM geosalary WHERE salary < ( SELECT MAX(salary) FROM geosalary ) Share. max() in my reduce class. DEPTNO ) AND e. SELECT name, MAX(salary) FROM employee WHERE salary < (SELECT MAX(salary) from employee); But this query returns just c as a result. In this case, selecting the employee names do not give you the right name and just return the first employee in the linked department! Select name of employee with max salary for given dept. Maximum salary based on column values in sql. I am trying to write a query where I can get employee name with the maximum % hike in salary from 2018 to 2019. is not null; it does not give me the data which includes the not null values of the comm. Display last name, job title of employees who have commission percentage and belongs to department 30. Salary into gr orderby gr. Dept Skip to main content. department_name) select deps. name AS MaxName, MAX(e1. The MAX. DEPTNO = 30; First of all, lose the Distinct(). abc | 35000. employee_name, c. employee_name, m. Treating same table as a separate two table. deptname,'max') as max_sal from employee e join department d on e. salary: SELECT * FROM department d1 WHERE salary > ALL I am having name column first name , last name then region column then salary column. Salary AS Salary FROM Employee I would like to know how can we apply the filter function after applying MAX function on data frame using Pyspark. First(). About; what is the query to return Name and Salary of employee Having Max Salary. select name, salary from employee e, select name, design from employee where sgrade – “s02” or sgrade = “so3; 3. salary from ( select first_name, salary, rank() over (order by salary desc) r from employees) v where v. OrderBy(x=>x. Syntax: Select Emp_name from table_name where Salary = ( Select Salary from table_name order by Salary DESC limit n-1,1); There can be another question like finding Nth Lowest Salary. table1 = e_id table2 GROUP BY(e_salary)` This article may be For an Employee table with columns EmpId, Name, Salary, is it possible to write a SQL query so that the result contains each employee's name and the average salary of all employees?. Salary > E1. SELECT emp_name, salary FROM ( SELECT emp_name, salary, ROW_NUMBER() OVER (ORDER BY salary ASC, emp_name ASC) AS rn_min, How to query employee name with max salary in each dept? My query: SELECT person_name, name_dep FROM Emp e INNER JOIN ( SELECT name_dep, MAX(salary) AS max_salary FROM Dep d GROUP BY id_dep ) d ON e. Find average salary of Your query is selecting all employees in department 30 who earn the highest overall salary. manager_id = m. SELECT MAX(Salary) FROM Employee WHERE Salary NOT IN WITH cte AS (SELECT dept, MAX( salary ) AS max_salary FROM emp GROUP BY dept ) SELECT * FROM emp INNER JOIN cte ON emp. But that will display all salary and the list of employees with that salary . select("deptno","sum",row_number(). e nth) highest salary from the table. If I am understanding your goal right and this is to retrieve the employees records of those who have the highest salary within their departments, I think a nested query is I am learning LINQ and I want to find third max salary using LINQ. What I tried:-I guess this is indirect way of asking how to list employees "based on" salary, In that case we can groupBy Salary. Given above is the employees table with five columns, with self-explanatory column names. sal) AS To Fetch The Names Of Workers Who Earn The Highest Salary. salary, b. you can solve this using with statement like this:. salary > 10000 GROUP BY d. Suppose we have a list of Employee objects { id, name, salary} . id AS department_id, d. But, the order among them is never guaranteed. An employee can have multiple salaries in your datamodel. Finding average highest salary. salary; Share. deptno=d. ). (Remove TOP 1 if you want all of them. Thanks for visiting Inflay. name AS department ,e. max_salary AND cte. Salary). SELECT e1. Select * From Employee E1 Where (2) = (Select Count(Distinct(E2. deptno; Which would at least provide the maximum salary of the department each employee belongs to and not just finance. I am asked to find most earliest hired employees. The ANSI standard method is: SELECT d. It is a common misconception that the join on condition may only contain key-related comparisons. salary from employees e join (select deptno,max(salary) as m from employees group by deptno) de on e. id = s. For max. I used below script to find the 3rd maximum salary. id IN (SELECT managerID FROM Employee))--or however you determine managers Find the employee who draws the maximum salary. DIFFERENCE FROM EMPLOYEES. Follow edited Dec 15, 2017 at 17:19. froxon froxon. JOIN JOBS WHERE The other two Answers both say you should not or cannot alter the objects being streamed. Find the employee with max salary in his department. from dept. company = e. name = e1. Email. min_salary from (select department,first_name as max_sal_emp,salary as max_salary from (select department,first_name,salary,dense_rank() over (partition by department order by salary desc) as max_sal_rank from employees)e where SELECT NAME, salary FROM (SELECT NAME, salary, ROWNUM r FROM (SELECT NAME, salary FROM employee ORDER BY salary DESC ) WHERE ROWNUM <= :N ) WHERE r >= :M Alternatively, you can use analytics: SELECT NAME It is a very easy process to find out the max salary from the table. company_name, e. id_dep = d. We will use the employees table to demonstrate how the MAX function works. This blog post will demonstrate how to retrieve the second and third highest salaries, including associated details However, what if I instead want to output names of people who have the minimum salary for their respective department (so Person 1 would not be returned anymore). Follow edited Jan 18, 2017 at 13:06. 22. Here is the current sql query: SELECT first_name, last_name, salary, department_id FROM employees WHERE salary IN ( SELECT MIN(salary) FROM employees GROUP BY department_id ); select d. I want to find the employees whose salary is greater than the average of their department and see their names, department_id, salary and It is "with ties" functionality what you're trying to achieve. salary select min(dob), max(doj) from employee; 3. Also, while this code snippet may solve the question, including an explanation really helps to improve the quality of your post. I am able to get only the max Salary by keeping the empty key in my map class and Math. For each employee, the query will display the name, the salary, and all other columns from the table employee b. How to get both c and d in result? I looked at bunch of similar questions posted but none of them mentioned how to get multiple rows for second highest salary. select * from employee where doj between ’09-feb-2006′ and ’08- aug -200%. About; Products Name. But I have to get the name of the employee as well. first_name, e. filter("rn==1"). department_name; It shows only departments which contains employees earning 10000 but I also need rest of departments with number 0 or - in column COUNT(e. age = e2. You can modify the content of the collection’s elements. First()}); foreach (var sal in ThirdHighestSal) { Console. EMPID JOIN (SELECT empid, MIN(salary) AS min_salary How to retrieve name of employee having salary greater than the average salary of their respective department. Return employee ID, first name, last name, salary, department name and city. //select people with second person's salary var q = from emp in Employees group emp by emp. Your Requirement: to get the "maximum salary with month and name, designation of an employee" Query: select name,Designation,max(salary) from T1 join T2 using (id) group by name; Result: select name,Designation,month,max(salary) from T1 join select emp_name, salary from ( select emp_name, salary, dense_rank() over (order by salary) as rnk from employees ) t where rnk <= 3; This will also deal with employees that have the same salary. salary = (select max(e2. : Query « Oracle PL / SQL. I succeeded to return the employee with the highest salary, but now I want to perform union with their Dno and the rest of the employee's row, how I can do this?. Return department ID, employee name, and salary. SAL FROM EMP e WHERE e. salary=de. 1st Table 2nd Table. e_name AND e1. Will . So the result might be more then three rows if more then one of the employees with the lowest salary have the same salary. DEPARTMENT_ID = e. N maximum salary: SELECT MIN(EmpSalary) FROM Salary WHERE EmpSalary IN(SELECT TOP N EmpSalary FROM Salary ORDER BY EmpSalary DESC) I need to find max and min salary for each department along with emp name . departments d ON d. SQL SUBQUERIES Exercise, Practice and Solution: From the following table, write a SQL query to find those employees who earn the highest salary in a department. Employee: Salary: This is the structure of both tables and I need to find the name of the person who has got highest salary in Feb 2014. TotalSalary=t. You can use a subquery You can go in different paths here. You can perform a CROSS JOIN of the employees table against itself to find the max name/salary with a query which finds the min name/salary. employee database SELECT name, MIN(salary) FROM employee GROUP BY deptid; Why I can't select "name" here? And what is the suggested query for this question? Skip to main content. SELECT MAX(Salary) as 'Salary' from EmployeeDetails where Salary NOT IN ( SELECT TOP 2 (SALARY) from EmployeeDetails ORDER BY Salary Desc ) SQL Fiddle. employees orderby employee. name, sum(s. emp another way using not exists i. employeeid, e. From the following table, write a SQL query to find those employees whose salary is in the range of minimum and maximum salary (Begin and end values are included. Is it appropriate to abbreviate authors’ names in function names, even with proper attribution? Is this particular argument, regarding Col 1:16, against the meaning "all other things" scripturally valid I have an employee table where the fields are: first_name, last_name, hire_date, salary, department_id, department_name, and so on. What is the result of the following SQL query? SELECT ename, esalary * 1. salary = (SELECT max Hi I used sequential Linq for getting nth highest salary from employee like. 4. Sample Data. SQL SELECT AVG; SQL SELECT MAX; SQL ADD COLUMN; How to use Auto-Increment in SQL; SQL Languages; SQL Arithmetic Operators; How to Use GROUP BY in SQL; How to Use ORDER BY in SQL; Trigger in SQL; EMPLOYEE_NAME SALARY; 1: JACK REACHER: 32000: 2: PADMA MAHESHWARI: 22000: 3: JOE PETRA: 41000: 4: AMBUJ AGRAWAL: When I try it without displaying department_id it works fine as : SQL> SELECT MAX(AVG(SALARY)) FROM EMPLOYEE GROUP BY DEPARTMENT_ID; MAX(AVG(SALARY)) ----- 800000 But when I . Return employee ID, employee name, job name, manager ID, hire date, salary, commission, department ID, and If, in the case of ties, you only want one, then order by and some form of getting one row works. I want to 2nd or 3rd(i. city -- Filtering rows based on the condition that the 'salary' of employee a is equal to the maximum salary within a specified date range Finding Nth highest salary in a table is the most common question asked in interviews. manager = e. You need the condition both in the inner query and the outer query: SELECT e. sal < e2. The id column is the primary key, and the salary column stores the salary of each employee. DEPARTMENT_NAME ORDER BY SUM(e. Table name is salary, columns are name,salary We can do this query by using limit command as select * from salary order by salary DESC limi select e. id, g. max_sal_emp, a. Date is simply Year from 2015 to 2019. 2. e_name = e2. I know how to query collections but I am unable to figure out out to solve this problem void Main() { List<Employee> SELECT emp_no, salary, Max(from_date) as "Most Current Salary Date" from salaries group by emp_no How to get depatment wise max salary as well as name of employee having it? 4. salary) sum_salary from departments d inner join employees e on e. But the result set doesn't make as much sense when there are ties on salary and the EMP_ID and FIRST_NAME don't ascend in lockstep. 3. The following SELECT statement returns the highest (maximum) salary of employees in the employees table. salary FROM employee e JOIN salary s ON e. For each employee, the query will display the name, the salary, all other columns from the table employee, and the number 1. hello. Required, but never shown Post Your . SELECT DISTINCT sal FROM downtodate1. That instruction is incorrect, as far as I know. wage descending select employee); The following should give you top 1 employee name and his/her salary which is equal to the minimum salary amongst all. Department into g let salary = g. salary<e2. I suspect they are confusing the rule that you should not modify the structure of the collection being streamed, such as adding/deleting objects to the source list. 1 FROM employee; Select one: a. it just gives me the field with the highest salary but no comm value. Use DISTINCT ON for a much simpler and faster query that does all you are asking for:. sal ) ORDER BY age DESC If two employees have the same age and salary, both will be returned Name Salary Jim 6 Foo 5 Bar 5 Steve 4 SELECT name, salary FROM employees WHERE salary = (SELECT MAX(salary) FROM employees WHERE salary < (SELECT MAX(salary) FROM employees)) Result --> Bar 5, Foo 5 EDIT: I took Manoj's second post, tweaked it, and made it a little more human readable. Salary let second = g. You will need to replace the word table with whatever your table name is. employeename, salaryData(d. 1 c. . emp_dept=d. Stack Overflow. (select AVG(Salary) A better query to find list of Employess who have max salary in their department? 0. Petter Friberg Select outemp. WriteLine("3rd highest sal is {0}",sal. DEPTNO = e. salary = (SELECT MAX(salary) FROM salary); Description: This query retrieves an employee who has the highest paid by using a subquery to find the maximum amount of salary in the salary table. id inner join salaries s on s. First_Name, outemp. select * from emp where sal = (select max(sal) from emp) and comm. DEPTNO, e. select max(sal) from emp where sal < (select max(sal) from emp) it works and it returns the right answer. department_id=e. Salary == salary) from emp in second select emp; SELECT d. company_Id where not exists ( select 1 from EMPLOYEE_TBL_ONE e2 where e2. Department,t. employees e JOIN hr. salary DESC ) AS rnk FROM locations l INNER JOIN departments d ON l. dept d join e. SELECT MAX(salary) FROM employee WHERE salary NOT IN (SELECT MAX(salary) FROM employee) mysql; sql; Share. Commented Jan 25, 2016 at 17:31. Check out this question and this answer for more information. company and To get the names of the employees with the 2nd highest distinct salary amount you can use. Consider the following table: Employee: CREATE TABLE: MySQL query to select maximum and minimum salary row - For this, use sub query along with MIN () and MAX (). Department ASC Suppose I have a table employee with id, user_name, salary. when I replace MAX(salary) with hardcoded value, it works as I expect: That would be something like this (presuming table names are emp and job): select e. It does not return the dept_no. When deciding the ties, all the ties are selected. Salary FROM(SELECT MAX(Salary) AS TotalSalary,Department FROM Employee GROUP BY Department) AS TempNew Inner Join Employee t ON TempNew. salary, DENSE_RANK() OVER (PARTITION BY d. I want a query to list Department wise highest salaries and name of the employee with that salary. Name from Employee a where a. This was the query I had. The main query filters the employees based on the condition that their salary equals the maximum For example, you might wish to know the maximum salary of all employees. alias("rn")). from this i want the person name who having max salary in east zone with vlookup function. ; lastname: The employee’s last name. Table SELECT ID,Salary FROM TABLE_NAME WHERE SALARY =(SELECT MAX(SALARY) FROM TABLE_NAME) Share. employee_id from emp e where e. emp_dept The sub query calculates the maximum salary for each department and then using the left join you can get it into the final table. have figured out a solution for the same. ENAME, e. Viewed 3k times -2 . salary > e1. dept = emp. Name AS Department, e1. Employee_ID, outemp. OrderByDescending(e => e. select name, max(sal) from emp where sal < (select max(sal) from emp) I get this error: The following solution works for MySQL, which was one of the tags you originally had when you posted your question. show() +-----+-----+ I have a table; containing 2 fields, name and salary. job_id = e. location_id = d. Departments outdept, (Select Max(e. salary = cte. empname, s. employee_id, a. EmpId Name Salary 1 Alice 12000 2 Bob 12000 3 Charlie 10000 4 Doug 6000 select e. Qstn: I want to display the (last_name, department_id, salary) of employees, who is earning the highest salary from every departments with the help of an SQL statement. manager ); Your issue is that a maximum salary under one manager may be the salary of someone else -- but not that manager's maximum. SELECT MAX(salary) AS "Highest salary" FROM employees; In this SQL MAX function example, we've aliased the SELECT a. SELECT DISTINCT ON (d. list(); I am getting maximum salary for each department. Emp table id ename ----- ----- 1 apv 2 sug 3 raj 4 ram 5 sam 6 apv1 7 sug1 8 raj1 9 ra EMP_ID NAME AGE ADDRESS SAL DEPT LOC 0 1 ghk 3 PTBP 23 IME bhmd 1 2 ghk 3 PTBP 23 IME bhmd 2 3 ghk 3 PTBP 23 IME bhmd 3 4 ghk 3 PTBP 23 IME-DATA bhmd 4 5 ghk 3 PTBP 24 IME-DATA bhmd 5 6 ghk 3 PTBP 23 IME bhmd 6 7 ghk 3 PTBP 23 IME bhmd 7 8 ghk 3 PTBP 29 IME-NA bhmd 8 9 ghk 3 PTBP 23 IME bhmd 9 10 ghk 3 PTBP 23 IME-NA I was working on the same SQL problem. sallary) from table u where u. 1. For each employee, Select e. So far I could manage getting the highest number of employees. emp_id = b. dep_name,cnt from deps where cnt=(select max(cnt) from For example, you might wish to know the maximum salary of all employees. emp_id, e. I was able to get the max Salary but not able to get the corresponding EmpName. getAllEmployee() group vr by vr. SQL Here you can see I write below code that gives output of id and salary but I want name and salary. my output should be james,40000 in this case. salary FROM departments d LEFT JOIN employees e ON e. first_name FROM employee_salary a JOIN employee b ON a. You can use rank(): SELECT w. 6. Below is my sample dataset. thanks in advance. Unfortunately mySQL doesn't support that (in the docs there is nothing to add to the "LIMIT" part of the query), so you have no other option rather than looking for max salary first and filter records afterwards. Salary as . id=managerId) as ManagerName,(select max(u. dep_id ORDER BY e. FIRSTNAME) AS FULLNAME, MAXSALARY FROM EMPLOYEES, (SELECT MAX(SALARY) AS MAXSALARY FROM EMPLOYEES) WHERE LASTNAME LIKE 'Z%'; But as Select name from employee where salary In (Select salary from employee group by salary having count(*)>1) Share. department_id group by dep. salary) AS sum_salary FROM EMPLOYEES e JOIN DEPARTMENTS d ON d. Remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion. 436954 Jul 9 2009 — edited Jul 12 2009. salary sql; select; Share. max_salary from job j where j. SELECT city, last_name, salary FROM ( SELECT l. To display both the maximum and minimum value, use To find out the maximum salary along with employee name I have written this query: SELECT name,salary FROM employee where salary = (select max(salary) from Above we demonstrate that we can use these two query. age AND e1. SELECT JOB_TITLE, FIRST_NAME, MAX_SALARY - Salary difference between employers, natural JOIN JOBS 49. salary); } As @lemon pointed out to you in comments, SQL Server doesn't support tuple comparison the way PostgreSQL and other RDBMS do. desc())). id) d. I know the query for second highest salary which is. department, g. Skip(2). name,e. department_id = dep. Employees outemp, HR. Follow select name as Employeename,(select t. As a result, "Highest salary" will display as the field name when the result set is returned. Select Max(Salary) from Employees where Salary < (Select Max(Salary) from Employees) I have a table named SalaryTable containing salaries of employee in various departments: dept_id name salary 12 a 100 13 b 200 12 c 300 14 d From the following table, write a SQL query to find employees along with their department details. Skip to main content. This is the query which retrieves the maximum number of employees. salary s " + "group by d. max_min_sal = E. Salary)) From Employee E2 Where E2. Improve this answer. To select the maximum salary from the employees table, we can use the following SQL query 1. SQL command for finding the second highest salary. Getting Max Salary For Each Employee. Ask Question Asked 9 years, 5 months ago. Example: Display the name of the employee who earns the highest salary. var ThirdHighestSal = from vr in Employee. I am trying to get the max salary for each employee. ename, e. job_id ); Share. – jauwad. employeenumber: Unique identifier for the employee. SOWJANYA SELECT TOP 1 * FROM TABLE NAME Share. department_name, COUNT(e. Sal),d. My table should look like. Selecting the Max Salary. Salary ORDER BY t. 21 3 3 [An editor is available at the bottom of the page to write and execute the scripts. where deptno in (select select ename of employee who earns 2nd max salary and works for location dallas select ename. dep_name, e. DEPARTMENT_NAME, SUM(e. So there is a table with employee name, salary and salary date as columns. sql-server; greatest-n-per-group; Share. SELECT * FROM employee WHERE salary IN(SELECT Max(salary) FROM employee UNION ALL SELECT Min(salary) FROM employee) INNER JOIN method SELECT * FROM employee E INNER JOIN (SELECT Max(salary) AS max_min_sal FROM employee UNION SELECT Min(salary) FROM employee) A ON A. Last_Name From Hr. id, d. Rest all other rows with sal value less than 5000 are not selected. So, your solution is fine for that case. CREATE TABLE employees ( id INT PRIMARY KEY, name VARCHAR(50), salary INT ); The employees table has three columns: id, name, and salary. Follow answered Sep 8, 2018 at If you're on Oracle database version lower than 12c, rank analytic function might help. name, max(s. employee_name AS manager_name FROM employee e JOIN employee m on e. first_name, a. salary) DESC 9. max_salary from employee e left join (select emp_dept,max(emp_sal) as max_salary from employee group by emp_dept) d ON e. SELECT a. SELECT DISTINCT Fname, Lname, salary FROM SELECT t. Ankit Wanwe Ankit Wanwe. emp_no = t. SELECT name FROM t1 WHERE t1. SELECT `employee_name`, `salary` FROM employees WHERE `salary` IN ( SELECT MAX (`salary`) FROM employees UNION Sample Solution: SELECT * FROM employees WHERE salary IN (SELECT max(salary) FROM employees); Sample Output: emp_id | emp_name | job_name | As short as the question: SELECT DeptID, MAX(Salary) FROM Employees GROUP BY DeptID. last_name, e. Improve this question. e_name as name2 FROM employee e1 JOIN employee e2 ON e1. Otherwise, SELECT g. empno,e. How can I get the name of the employee with the max salary ? Cheers for the help folks. How to get second-highest salary SELECT dep_name, salary FROM ( SELECT d. salary) from Employee e1,Employee e2 where e1. Modified 9 years, 4 months ago. I know functi 1. i. id ORDER BY d. SELECT MAX(salary) AS "Highest salary" FROM employees; In this SQL MAX function example, we've aliased the MAX(salary) field as "Highest salary". employee_id) as cnt from departments dep inner join employees emp on emp. using dense_rank() with join; select a. Return complete information about the employees. What this does is find the max salary and then uses that in the query to find all people with that salary. So you want some random person's name, and the max salary of all employees? – Kevin. Add a comment | 2 Answers Sorted by: Reset to default 4 . id WHERE s. Lets we have 2 standard tables Employees and Departments CREATE TABLE departments ( id SERIAL PRIMARY KEY, name VARCHAR ); CREATE TABLE employees ( id SERIAL PRIMARY KEY, department_id IN Skip to main content. At the moment, I've just selected all of the people, ordered them by wage and entered them in a listbox very simply by doing this. df_sum. Follow I cam across this question which I would request help for. Key descending select( new {salary=gr. Just in case someone may need help. salary; Note also that the ON condition contains the salary comparison. Name AS Employee, e1. KEEP solution provides a coherent answer with the sample data, especially given there are no ties on max salary. DEPARTMENT_ID GROUP BY d. In the second table, I have employee details (such as salary, location, join date, projects handled, designation SELECT d. salary) from employee e2 where e2. SAL = (SELECT MAX(e2. To me n-1 is not I'm new to SQL, and I'm trying to get names of employees working in the department where the employee receives the highest salary. Here is the table 1st is emp_info & 2nd is emp_salary. createQuery( "select d. Use rank instead to get the salary in the decent order and get the first 10 of them:. An employee's (total) salary hence is the sum of these. I want to retrieve third highest salary from tblEmployee table alongwith the name of employee. salary > (select j. sal) AS MaxSalary, e2. One obvious solution is VLOOKUP: =VLOOKUP(E2, A1:B6, 2) After that you would need to add a cell for every column you want to add, changing the third parameter on each cell. employee_id). ; level: The employee’s level In the first table I have employee id's and their names. managerId=managerId) as MaxSalary from table This will give you the expected result Here is the query with which you can fetch the salary of Bob: SELECT Salary FROM salary WHERE EmpId = 2; Now you want to fetch all names and salaries of employees who have higher salary than what you fount with the query above. first_name, v. e product details ‘product’ and ‘quantity’ using joins. 1). Share. m; – Amit. Oracle 11g R2 Schema Setup:. location_id List<Object[]> results = session. Follow answered Sep 25, 2018 at select e. Commented Aug 8, 2017 at 1:21. salary from employees e inner join titles t on e. id, SQL SUBQUERIES Exercise, Practice and Solution: From the following table, write a SQL query to search for employees who receive such a salary, which is the maximum salary for salaried employees, hired between January 1st, 2002 and December 31st, 2003. * FROM DATA D Name - Jess Jane Age - 40 Department - Kitchen Wage - 16,000you get the idea. var item = (from employee in employeeList. e_name as name1, e2. com . Improve The main query filters according to both parameters: name and max salary. r <= 10 i have a table called employees which i have name, department_id and salary in it. If it does, then we will display all the details of the employees. department_id = d. name"). The groupings are by definition unique. department_name as dep_name, count(emp. SELECT DISTINCT T Limit The Query To Display Only The Top 3 Highest Paid Employees. drop("rn"). SAL) FROM EMP e2 WHERE e2. department_id WHERE e. orderBy(df_sum["sum"]. SELECT e. I have the table as follows: Display employee name, total salary of each employee. Here is a way to do this task using the dense_rank () function. Name Sal Product quantity Name4 50000 watch 1 i have 'id' has primary key in customers table and 'clent_id' as foreign key in products table. EmployeeName,t. name AS employee, e. ;WITH T AS ( SELECT *, DENSE_RANK() OVER (ORDER BY Salary Desc) AS Rnk FROM Employees ) SELECT Name FROM T WHERE Rnk=2; SQL> with emp (employee_id, name, months, salary) as 2 (select 12, 'ami', 15, 1230 from dual union all 3 select 14, 'bik', 1 , 678 from dual union all 4 select 15, 'tom', 10, 500 from dual union all 5 select 16, 'bob', 12, 3456 from dual union all 6 select 17, 'wil', 1 , 9000 from dual union all 7 select 18, 'tim', 14, 1239 from dual union all 8 select 22, 'jil', 15, 1230 from dual 9 ), SELECT `employee_name`,`salary` FROM employees WHERE `salary` IN ((SELECT MAX(salary) FROM employees) , (SELECT MIN(salary) FROM employees)); to find Max And Min Salary Of Employees With Employee Name In MySql. city, e. employee emp job dept name emp salary salary grade ----- ----- ----- ----- ----- james clerk sales 950 1 smith clerk research 800 1 adams clerk research 1100 1 martin salesman sales 1250 2 ward salesman sales 1250 2 miller clerk accounting 1300 2 allen salesman sales 1600 3 turner salesman sales 1500 3 blake manager research 2850 4 clark manager accounting 2450 4 This query gives you a list of departments, with that department's highest paid salary, if exists, or null otherwise. salary DESC) AS rnk How to get the firstname and max salary of employee according to their department from this query? 1. SQL I don't have your tables so I created views out of Scott's ones, to simulate what you have. For sample rows: SQL> select * from employee order by salary desc; ENAME SALARY ----- ----- KING 5000 --> highest salary FORD 3000 --> Ford and Scott "share" the 2nd SCOTT 3000 --> highest salary JONES 2975 BLAKE 2850 CLARK 2450 ALLEN 1600 TURNER 1500 with salaries as ( select 1 as id, 'Kobe' as name, 50000 as salary union all select 2, 'Lebron', 1000000 union all select 3, 'Steph', 222222 ) select name from salaries order by salary desc limit 1 Output: Find the top 2 employees who have the highest salary. You can use MAX OVER to find the maximum sum: Not sure which is your desired behavior so here are two versions. Salary) I want LINQ get max of Amount but return name. Skip(1). over(Window. dept How to get department wise highest salary and highest salary holder Employee name,consider 3 tables are joined using keys. SQL subqueries on employee Database, Practice and Solution: From the following table, write a SQL query to find the highest paid employee. *, RANK() OVER (ORDER BY Salary DESC) as Seq FROM worker w ) w WHERE seq = 1; By this way, you will get name of workers who has earned highest salary. create table employee( emp_no integer primary key ,lastname varchar2(20) not null ,salary number(3) ); insert into employee(emp_no,lastname,salary) values(1,'Tomy',2); insert into employee(emp_no,lastname,salary) values(2,'Jacky',3); insert into You can use the DENSE_RANK analytic function (which will return all employees with the maximum salary per city):. Query results shows all employees details whose salary is greater than the average salary of that department. select a. Imagine you have a table like so: VLOOKUP Solution. I googled but found answers like this, which lists only the department and salary. salary FROM geeksforgeeks g JOIN (SELECT department, AVG(salary) FROM (WITH DATA AS -- creating dummy data ( SELECT 'MOHAN' AS NAME, 200 AS SALARY FROM DUAL UNION ALL SELECT 'AKSHAY' AS NAME, 500 AS SALARY FROM DUAL UNION ALL SELECT 'HARI' AS NAME, 300 AS SALARY FROM DUAL UNION ALL SELECT 'RAM' AS NAME, 400 AS SALARY FROM DUAL ) SELECT D. id_dep Find the name and Job of the emps who earn Max salary and Commission. There is a tie on sal with value 5000, and both are selected. Department and TempNew. *, min_salary, max_salary FROM EMPDETAILS d JOIN EMPLOYEE e ON d. company = c. location_id ORDER BY e. Here's the answer I came up with. Comments. 1 WHERE MAX(salary) = salary GROUP BY department. I wrote the below query but stuck for hours at the same. In sql, select ename from emp where sal=(select max(sal) from emp) ; I want to apply same logic on dataframe in Pyspark. So, if I change my HQL to : I have two tables from which i want to get maximum salary & the employee name. 7k 13 13 gold Name. emp_no inner join salaries s on e. deptno, e.